#### Michael Lawrence Morton's Matrix Message #48 Munck's "Peripheral Pyramid" Its Firm Tie to 'The Tetrahedral Grid LAT'

In his self-published book, "The Code, Volume A" (1993), Carl P.Munck, Sr. discusses "The Temple of the Giant Jaguar" at Tikal in Guatemala. This structure is also known as "Temple I" at Tikal. Its facade faces to the west.

Munck calls it "The Peripheral Pyramid", because he found that it "knows" its own longitude backwards and forwards ... using the Giza prime meridian that passes through the center of The Great Pyramid. It's as if this pyramid can "see" all the way around the Earth, both east and west, to the true prime meridian of this ancient 'matrix'.

How do we know that it knows its own longitude, both ways ? If we multiply its numbers ... of degrees X minutes X seconds ... BOTH WAYS, east and west, from the meridian passing through the center of The Great Pyramid of Giza ... we get the *exact* same Grid Longitude figure ... both "E.Giza" AND "W.Giza". And here they are ...

Grid LONG 120 (deg) X 45 (min) X 22.91831181 (sec) W.Giza ... = 123758.8838 W.Giza ... = 2160 Radians (deg). W.Greenwich 89 deg 37 min 22.11831181 sec

Grid LONG 239 (deg) X 14 (min) X 36.98711411 (sec) E.Giza ... = 123758.8838 E.Giza. E.Greenwich 270 deg 22 min 37.78711411 sec

Notice that the Grid LONGs are identical (Munck, 1993).

To pre-empt the possible objection that there is a "gap" of a little less than 9 Feet 'between' the 2 longitudes :

Notice the precise number of arc-seconds of West Giza longitude ... "22.91831181" ... this is *exactly* 2/5ths of The Radian (deg). This is a deliberate statement by the designers/builders ... affirming their use of the 360-degree system. The Radian (deg) is equal to ... 360 / 2Pi ... = 57.29577951 arc-degrees. 57.29577951 X 2/5ths = 22.91831181.

And that is why "they" didn't see the less-than-9-feet 'gap' as anything that would "invalidate" this work of genius, in the least.

What is the Grid LAT, and Grid POINT Value, of Temple I at Tikal ?

Grid LAT 17 (deg) X 13 (min) X 12.61786429 (sec) North ... = 2788.548009 North ... = Pi X (Square Root of Volume of a Sphere) ... = 3.141592654 X 887.6223994 . Note : we assume the radius of the 'given' sphere to be Radian (deg) ... (57.29577951 X 57.29577951) X 240 = 787873.5239 Cubic Arc-degrees, the Volume of the 'given' sphere. Square Root of 787873.5239 ... = 887.6223994

Grid POINT Value Temple I at Tikal 123758.8838 / 2788.548009 ... = 44.38112 (Munck, 1993).

Now ... to show the specific relationship of the 'Tetrahedral Grid LAT' (Morton, 1999) to Temple I at Tikal ... I will divide 44.38112 by the Pi constant ...

44.38112 / 3.141592654 = 123758.8838 / 8760.481939

Notice that 8760.481939 is the 'Tetrahedral Grid LAT' (Morton, 1999) ... based on a translation of the Hoagland Tetrahedral Latitude of 19.4712 degrees north and south (See Richard C. Hoagland's book, "The Monuments of Mars"). 19 (deg) X 28 (min) X 16.46707131 (sec) = 8760.481939 North/South. { Also see my article at mat_46.htm Matrix Message #46 } My Revised 'Tetrahedral Grid LAT'

So ... there we have the Grid LONG (123758.8838 E.Giza and W.Giza) ... of Temple I at Tikal ... precisely relating to not only the Grid POINT Value of Temple I itself ... but also, simultaneously, 'directly' to the 'Tetrahedral Grid LAT' ... via ... the Pi constant !!! All in one neat equation .

A further note : Notice the number of degrees of the West Giza longitude of Temple I at Tikal ... "120" ... a very "tetrahedral" number, of course. So; we have here a reference to the equilateral triangle (2-D) azimuth-points of its vertices ... 120 degrees and 240 degrees, assuming a due-north position for one of the vertices. This, of course, is a 2-D representation of a tetrahedron.

-- Michael L. Morton

NOTE: Copying and circulation of this paper is encouraged, but please include the author's copyright. Thanks ~ MLM

(c) 1999 by mailto:Milamo@aol.com Michael Lawrence Morton ~ArchaeocryptographerTo contact the author please e-mail above or telephone: 412-819-0202 Pittsburgh, PA, USA.==

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